KW/Ton - Carrier

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Permalink Reply by JEPER M.PARDE on May 16, 2009 at 3:29am

Mr.Lucky Chan e2 ang pagkakaalam ko 1 watt =3.414368btu/hr 1 kilowatt = 1.34 horsepower ikaw na bahala mag compute yan na ang basehan . hope it will help you! ayon sa data mo kc carrier unit 38000 btu/hr yan more or less 3 ton yan

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Permalink Reply by Chillerman on May 16, 2009 at 5:18am

Hello Laki Tian...

Play with this formulas:

KW/ton = 12 / EER
KW/ton = 12 / (COP x 3.412)
COP = EER / 3.412
COP = 12 / (KW/ton) / 3.412
EER = 12 / KW/ton
EER = COP x 3.412

If chillers efficiency is rated at 1 KW/ton,

COP = 3.5
EER = 12

The term kW/ton is commonly used for larger commercial and industrial air-conditioning, heat pump and refrigeration systems.

The term is defined as the ratio of energy consumption in kW to the rate of heat removal in tons at the rated condition. The lower the kW/ton the more efficient the system.

kW/ton = Pc / Er (1)

where

Pc = energy consumption (kW)

Er = heat removed (ton)

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Permalink Reply by Chillerman on May 16, 2009 at 8:07pm

Try mo rin gamitin Power Converter Tool sa Homepage

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Permalink Reply by Chillerman on May 22, 2009 at 11:49pm

Using the attached Carrier Data ( page 3 )consider this value:
KW/ton = 12 / EER
= 12/ 11.2
KW/ton = 1.07

Chillerman said:

Hello Laki Tian...

Play with this formulas:

KW/ton = 12 / EER
KW/ton = 12 / (COP x 3.412)
COP = EER / 3.412
COP = 12 / (KW/ton) / 3.412
EER = 12 / KW/ton
EER = COP x 3.412

If chillers efficiency is rated at 1 KW/ton,

COP = 3.5
EER = 12

The term kW/ton is commonly used for larger commercial and industrial air-conditioning, heat pump and refrigeration systems.

The term is defined as the ratio of energy consumption in kW to the rate of heat removal in tons at the rated condition. The lower the kW/ton the more efficient the system.

kW/ton = Pc / Er (1)

where

Pc = energy consumption (kW)

Er = heat removed (ton)

Attachments:

• Carrier.pdf, 2.1 MB

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Permalink Reply by Adonis on June 18, 2009 at 11:07pm

hELLO, i HOPE DI PA LATE ang reply ko,

your unit is air cooled condensing unit with nominal capacity of 25tons with 460v/3ph/60hz supply. H means high efficiency air cooled condensing units ( as per model).

The 1.07 kw/ton is the kw/ton if the unit is brand new or a factory test results.

My approach is get the input kw from the actual amps, voltage (ave), apply the sq root of 3 and the actual power factor. You have to do some math to get the input kw.

After you get the input kw, divide it by the actual cooling capacity. you can get the actual cooling capacity by using a testing machine, otherwise, you can use the factory supplied data which is 290000 Btuh or 24.167 tons.

You should get a little bit higher than 1.07 kw/ton

One suggestion, if you're boss was asking for kw/ton of the condensing unit, you better suggest to him to include the indoor unit (AHU) in computing for the actual kw/ton because a/c units (AHU & ACCU) are working together as a system. You can't evaluate it accurately if you only look on the ACCU alone. It should come together as a system.


Hope this will help.

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